Asked by Chopsticks
                (2x/2x) + 1 
== 1?
            
        == 1?
Answers
                    Answered by
            Ms. Sue
            
    Doesn't (2x/2x) = 1??
    
                    Answered by
            Chopsticks
            
    i typed it wrong 
2x/2x+1
    
2x/2x+1
                    Answered by
            Mishi Couture
            
    x=0
    
                    Answered by
            Ms. Sue
            
    Still -- I may be wrong -- but any number divided by the same number is 1 -- isn't it?
1 + 1 = 2
    
1 + 1 = 2
                    Answered by
            Chopsticks
            
    oh u looked at the problem wrong. the 2x+1 is in the denominiator
    
                    Answered by
            Mishi Couture
            
    huh? Do you have to find x?
but 2x/2x + 1 would equal 1 cause the terms "cancel out"
    
but 2x/2x + 1 would equal 1 cause the terms "cancel out"
                    Answered by
            Reiny
            
    2x/2x+1  is the same as (2x/2x) + 1 
did you mean 2x/(2x + 1) ?
If so, what do you want done with it?
    
did you mean 2x/(2x + 1) ?
If so, what do you want done with it?
                    Answered by
            Chopsticks
            
    2x/(2x+1)  simplify it
    
                    Answered by
            Mishi Couture
            
    yea..
so that would be 1
    
so that would be 1
                    Answered by
            Reiny
            
    2x/(2x+1) does not simplify any more.
no matter what x you choose, the numerator is an even number and the denominator is the next number, which would then be odd.
Such a fraction does not reduce further.
e.g. 2/5, 10,11, etc
    
no matter what x you choose, the numerator is an even number and the denominator is the next number, which would then be odd.
Such a fraction does not reduce further.
e.g. 2/5, 10,11, etc
                    Answered by
            Chopsticks
            
    what if it was 2x/2x + 1 
where the 2x+1 is combined under the denominator
    
where the 2x+1 is combined under the denominator
                    Answered by
            Reiny
            
    umhh, that is what I have been saying
Look at the 10:13 post
    
Look at the 10:13 post
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