2Hg + O2---> 2HgO

If the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the Mercury and Oxygen on the reactants side of the equation?

3 answers

The molar mass of mercuric oxide (HgO) is 216.6 g/mol. Since the total mass of the product (HgO) is 433.2 grams, we can divide this by the molar mass to find the number of moles of HgO:

433.2 g HgO / 216.6 g/mol = 2 moles HgO

According to the balanced equation, 2 moles of HgO are formed from 2 moles of mercury (Hg) and 1 mole of oxygen (O2). Therefore, the total molar mass of mercury and oxygen on the reactant side of the equation is:

2 moles HgO x (2 moles Hg / 2 moles HgO) x (200.6 g Hg / 1 mole Hg) = 401.2 grams Hg

2 moles HgO x (1 mole O2 / 2 moles HgO) x (32 g O2 / 1 mole O2) = 32 grams O2

Adding these two masses together, we find:

401.2 grams Hg + 32 grams O2 = 433.2 grams
3.1- the element is in group 1a and has 1 valence electron

3.2 -
1physical
2chemical

4 -
compund has 7 total atoms
2
this formula contains 3
3
this compund is made of sodium
1

4.1-
coefficiant front

5- 433.2

5.1- chemical element

6-
reactant
product
product

6.1- yes

6.2- _ _
reactants
substances
1-the red circles because they are protons in the nucleus
1.2-protons nucleus

2-
has 1 valence electron
is in group 2a
has 10 protons
2.1- valence

3- the elements in yellow are in the same
column group
row period

3.1- the element is in group 1a and has 1 valence electron

3.2 -
1physical
2chemical

4 -
compund has 7 total atoms
2
this formula contains 3
3
this compund is made of sodium
1

4.1-
coefficiant front

5- 433.2

5.1- chemical element

6-
reactant
product
product

6.1- yes

6.2- _ _
reactants
substances
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