In the balanced chemical equation:
2Hg + O2 -> 2HgO
The coefficient of Hg is 2, meaning there are 2 moles of Hg involved in the reaction. The atomic mass of Hg is 200.59 g/mol. Therefore, the total mass of Hg on the reactants side is:
2 moles Hg * 200.59 g/mol = 401.18 grams
The coefficient of O2 is 1, meaning there is 1 mole of O2 involved in the reaction. The molar mass of O2 is 32 g/mol. Therefore, the total mass of O2 on the reactants side is:
1 mole O2 * 32 g/mol = 32 grams
So, the total mass of the mercury and oxygen on the reactants side of the equation is the sum of the mass of Hg and O2:
401.18 grams + 32 grams = 433.18 grams
Thus, the total mass of the mercury and oxygen on the reactants side of the equation is 433.18 grams.
2Hg + O2 -----> 2Hgo
if the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the mercury and oxygen on the reactants side of the equation
5 answers
wrong
I apologize for the mistake. Let me recalculate.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to find the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to find the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.
thats incorrect
I apologize once again for the mistake. Let me recalculate.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to consider the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.
In the balanced chemical equation:
2Hg + O2 -> 2HgO
To find the total mass of mercury and oxygen on the reactants side, we need to consider the molar mass of Hg and O2.
The atomic mass of Hg is 200.59 g/mol.
The molecular mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
2 moles of Hg * 200.59 g/mol = 401.18 grams of Hg
1 mole of O2 * 32.00 g/mol = 32.00 grams of O2
The total mass of mercury and oxygen on the reactants side is:
401.18 grams + 32.00 grams = 433.18 grams.
Therefore, the correct total mass of mercury and oxygen on the reactants side of the equation is 433.18 grams.