2CH3CH2CH2OH(l)+9O2(g)→6CO2(g)+8H2O(g)

Question

I have to find the delta G

delta G of CH3CH2CH2OH(l)=−360.5 KJ/Mol
delta G of O2(g)=0 KJ/Mol
delta G of CO2(g)=−394.4 KJ/Mol
delta G of H20(g)=−228.6 KJ/Mol

I keep getting -3426.2 KJ/Mol but its not correct.

Answer 1

Hess Law:
sum heats products-sum reactants
8*-228.6 + 6*-394.4-2*360.5=

which does not match your answer.

Answer 2

Oh it sums up the heat? I thought it was delta G(products)-Delta G(reactants) wouldn't that then be
8*-228.6 + 6*-394.4-2*(-360.5)= giving you -3426.2 KJ/Mol. Could you explain why you made the 360.5 positive?
Thanks.

Answer 3

Because I made a typo error on the sign on the 360, and you have the correct procedure. It is -3426.2Kj

Answer 4

I am doing this assignment for mastering chemistry and It just keeps telling me that it is wrong, I have no idea what the issue is.