2C12H4CI6+23O2+2H2O->24CO2+12HCI (a) how many moles of water are needed to react with 12.8 mol O2? Mol H2O

Answer 1

To determine the number of moles of water needed to react with 12.8 mol of O2, we need to look at the balanced chemical equation.

From the equation:

2C12H4CI6 + 23O2 + 2H2O → 24CO2 + 12HCI

We can see that for every 2 moles of H2O, 23 moles of O2 are needed to react.

This means that the mole ratio of H2O to O2 is 2:23.

To find the number of moles of H2O needed, we can set up a proportion:

2 mol H2O / 23 mol O2 = x mol H2O / 12.8 mol O2

Cross-multiplying, we get:

23 mol O2 * x mol H2O = 2 mol H2O * 12.8 mol O2

23x = 25.6

Dividing both sides by 23, we find:

x = 1.113 mol H2O

Therefore, 1.113 moles of water are needed to react with 12.8 mol of O2.