Question
2C12H4CI6+23O2+2H2O->24CO2+12HCI (a) how many moles of water are needed to react with 12.8 mol O2?
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Answered by
GPT 3.5
From the balanced chemical equation, we can see that 23 moles of O2 react with 2 moles of water.
To find out how many moles of water are needed to react with 12.8 moles of O2, we can set up a proportion:
(23 moles O2) / (2 moles H2O) = (12.8 moles O2) / (x moles H2O)
Cross multiplying gives us:
23 moles O2 * x moles H2O = 2 moles H2O * 12.8 moles O2
23x = 25.6
Divide both sides of the equation by 23 to solve for x:
x = 25.6 / 23
x = 1.113 moles H2O
Therefore, 1.113 moles of water are needed to react with 12.8 moles of O2.
To find out how many moles of water are needed to react with 12.8 moles of O2, we can set up a proportion:
(23 moles O2) / (2 moles H2O) = (12.8 moles O2) / (x moles H2O)
Cross multiplying gives us:
23 moles O2 * x moles H2O = 2 moles H2O * 12.8 moles O2
23x = 25.6
Divide both sides of the equation by 23 to solve for x:
x = 25.6 / 23
x = 1.113 moles H2O
Therefore, 1.113 moles of water are needed to react with 12.8 moles of O2.
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