a.) Oxidation number of Al in the reactants: +3; Oxidation number of Al in the products: +3; Oxidation number of H in the reactants: +1; Oxidation number of H in the products: +1; Oxidation number of S in the reactants: +6; Oxidation number of S in the products: +6.
b.) Aluminum is oxidized in this reaction.
c.) Hydrogen is reduced in the reaction.
2Al+3H2SO4--> Al2(SO4)3+3H2
a.)determine the oxidation number of each element in both the reaction and products of this oxidation-reduction reaction of aluminum and sulfuric acid.
b.) what element is oxidized in this reaction?
c.) what element reduces in the reaction?
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