Question

Solve the system of equations below.
5x+3y=2
4x+3y=1

Answer 1

You sure?

Answer 2

To solve this system of equations, we can use the method of substitution or elimination.

Using substitution:

From the first equation, we can isolate y:

5x + 3y = 2
3y = 2 - 5x
y = (2 - 5x) / 3

Now substitute y into the second equation:

4x + 3((2 - 5x) / 3) = 1
4x + 2 - 5x = 1
-x + 2 = 1
-x = -1
x = 1

Now substitute x = 1 back into the first equation to solve for y:

5(1) + 3y = 2
5 + 3y = 2
3y = -3
y = -1

Therefore, the solution to the system of equations is x = 1 and y = -1.

Answer 3

Let's try solving the system of equations using the method of elimination.

Given equations:
5x + 3y = 2 ...(1)
4x + 3y = 1 ...(2)

To eliminate y, we can subtract equation (2) from equation (1):
(5x + 3y) - (4x + 3y) = 2 - 1
5x + 3y - 4x - 3y = 1
x = 1

Now that we found x = 1, we can substitute it back into equation (1) to solve for y:
5(1) + 3y = 2
5 + 3y = 2
3y = -3
y = -1

Therefore, the correct solution to the system of equations is x = 1 and y = -1.