If the initial velocity is horizontal, it has not influence on the time of fall.
Time of fall is determined by the height, and by gravity.
h=1/2 g t^2
solve for t, time.
A person standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 23 m/s. The cliff is h = 54 m above the water's surface. How long does it take for the stone to fall to the water?
With what speed does it strike the water?
4 answers
Thank you.
How would I calculate the speed?
the vertical speed is
vf= g *time
the horizontal speed is the kicking speed.
Vftotal=sqrt (Vh^2+ Vvf^2)
vf= g *time
the horizontal speed is the kicking speed.
Vftotal=sqrt (Vh^2+ Vvf^2)
1 answer