a jar contaiins six blue marbles and three red marbles suppose you choose a marbale at random and do not replace it then you choose a second marble find the probability of the following event both of the selected marbles are red

To find the probability of both selected marbles being red, we need to find the probability of selecting a red marble for the first draw and then for the second draw without replacement.

There are 3 red marbles out of a total of 9 marbles in the jar.

Probability of selecting a red marble on the first draw = 3/9 = 1/3

Since we do not replace the marble, there are now only 2 red marbles left out of 8 total marbles.

Probability of selecting a red marble on the second draw = 2/8 = 1/4

Therefore, the probability of both selected marbles being red is:

(1/3) * (1/4) = 1/12

So, the probability of both selected marbles being red is 1/12.