Question

a jar contaiins six blue marbles and three red marbles suppose you choose a marbale at random and do not replace it then you choose a second marble find the probability of the following event both of the selected marbles are red

Answer 1

To find the probability of both selected marbles being red, we need to find the probability of selecting a red marble for the first draw and then for the second draw without replacement.

There are 3 red marbles out of a total of 9 marbles in the jar.

Probability of selecting a red marble on the first draw = 3/9 = 1/3

Since we do not replace the marble, there are now only 2 red marbles left out of 8 total marbles.

Probability of selecting a red marble on the second draw = 2/8 = 1/4

Therefore, the probability of both selected marbles being red is:

(1/3) * (1/4) = 1/12

So, the probability of both selected marbles being red is 1/12.