Question

You have 1 red marble, 1 blue marble, 1 yellow marble and 1 white marble. You draw 2 marbled out of the bag without replacing. What is the probability that you may choose 1 red marble?
There are 6 ways you can draw the two marbles to include one red:

RB,RY,RW,BR,YR,WR

There are 4P2 = 12 ways to draw any two marbles

So, P(one red) = 6/12 = 1/2

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