Asked by Tim
If each side of a regular pentagon is X2 + 17 and each side of a regular hexagon is x2 + 2x, for what value or values of x will be the perimeters of the figures be equal
Answers
Answered by
drwls
Just set the perimeteres equal:
5(x^2 +17) = 6(x^2 + 2x)
and solve the resulting quadratic.
x^2 +12x -85 = 0
(x + 17)(x-5) = 0
Negative x solutions are not of interest, so the answer is x=5
5(x^2 +17) = 6(x^2 + 2x)
and solve the resulting quadratic.
x^2 +12x -85 = 0
(x + 17)(x-5) = 0
Negative x solutions are not of interest, so the answer is x=5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.