Asked by Haley
This regular octagon has a side length 15.0cm. Determine the distance from one vertex to the opposite vertex, measured through the centre of the octagon. Give your answer to to the nearest tenth of a centimeter.
Answers
Answered by
Steve
Divide the octagon into 8 congruent isosceles triangles, each with base 15.
Since the vertex angle is 360/8 = 45°, each of the slant sides has length
7.5/sin22.5° = 19.6
The desired distance is twice the length of one of these sides, or 39.2
Since the vertex angle is 360/8 = 45°, each of the slant sides has length
7.5/sin22.5° = 19.6
The desired distance is twice the length of one of these sides, or 39.2
Answered by
Anonymous
Where did you get 7.5 and 22...
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