Asked by george
If sinu= (-5/7) and pie<u< (3pie/2) find sin 2u
Answers
Answered by
MathMate
Calculate sin(2u) using the identity:
sin(2x)=2sin(x)cos(x) ....(1)
From "pie<u< (3pie/2)"
we conclude that u is in the third quadrant where sin(u)<0 and cos(u)<0.
From sin(u)=(-5/7), calculate cos(u) using cos²(u)+sin²(u)=1.
Make sure the value of both sin(u) and cos(u) are negative and substitute in equation (1) above.
sin(2x)=2sin(x)cos(x) ....(1)
From "pie<u< (3pie/2)"
we conclude that u is in the third quadrant where sin(u)<0 and cos(u)<0.
From sin(u)=(-5/7), calculate cos(u) using cos²(u)+sin²(u)=1.
Make sure the value of both sin(u) and cos(u) are negative and substitute in equation (1) above.
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