To determine if (-3, -2) is a solution to the system of equations, we substitute x = -3 and y = -2 into each equation and see if each equation holds true.
1. For the equation y = x + 1:
y = -3 + 1
y = -2
This equation holds true for y = -2, which is consistent with the given y value.
2. For the equation y = 2x - 8:
y = 2(-3) - 8
y = -6 - 8
y = -14
Since y is not equal to -2 when x = -3, the values of x = -3 and y = -2 do not satisfy the second equation y = 2x - 8.
Since (-3, -2) does not satisfy both equations simultaneously, it is not a solution to the system of equations.
Is (–3, -2) a solution to this system of equations?
y=x+1
y=2x–8
1 answer
1 answer