Question
a gas at 1.5 atm had its pressure decreased to 0.50 atm producing a new volume of 750 mL. what was its original volume
Answers
GPT 3.5
To solve this problem, we can use the combined gas law formula:
P1V1/T1 = P2V2/T2
Where:
P1 = 1.5 atm
V1 = original volume (unknown)
T1 = unknown
P2 = 0.50 atm
V2 = 750 mL
T2 = unknown
Now we can rearrange the formula to solve for V1:
V1 = (P2V2*T1) / (P1*T2)
Since the temperature and moles of gas remain constant, we can cancel them out from the equation. We are left with:
V1 = (P2V2) / P1
V1 = (0.50 atm * 750 mL) / 1.5 atm
V1 = 375 mL
Therefore, the original volume of the gas was 375 mL.
P1V1/T1 = P2V2/T2
Where:
P1 = 1.5 atm
V1 = original volume (unknown)
T1 = unknown
P2 = 0.50 atm
V2 = 750 mL
T2 = unknown
Now we can rearrange the formula to solve for V1:
V1 = (P2V2*T1) / (P1*T2)
Since the temperature and moles of gas remain constant, we can cancel them out from the equation. We are left with:
V1 = (P2V2) / P1
V1 = (0.50 atm * 750 mL) / 1.5 atm
V1 = 375 mL
Therefore, the original volume of the gas was 375 mL.