Asked by Tanisha
The pressure of 6.0 L of an ideal gas in a flexible container is decreased to one-half of its original pressure, and its absolute temperature is decreased to one-seventh of the original. What is the final volume of the gas?
Answers
Answered by
bobpursley
PV=nRT
v= nRT/P
It looks to me as t= 1/7 To and P is 1/2 Po
V= nRTo*2/7Po or volume is 2/7 of 6 liters.
v= nRT/P
It looks to me as t= 1/7 To and P is 1/2 Po
V= nRTo*2/7Po or volume is 2/7 of 6 liters.
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