Question
A ball rolls down an incline at a constant acceleration of 2 m/s^2. What is the velocity of the ball after 8.5 s?
How far does the ball roll in 10s? How far does the ball roll in the seventh second?
Answers
a = (Vf - Vi)/t
d = Vi*t + (1/2)a*t^2
where Vf = final velocity, and Vi = initial velocity.
d = Vi*t + (1/2)a*t^2
where Vf = final velocity, and Vi = initial velocity.
9m/s