Question


A ball rolls down an incline at a constant acceleration of 2 m/s^2. What is the velocity of the ball after 8.5 s?
How far does the ball roll in 10s? How far does the ball roll in the seventh second?

Answers

a = (Vf - Vi)/t

d = Vi*t + (1/2)a*t^2

where Vf = final velocity, and Vi = initial velocity.
9m/s

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