simplify 6 over squareroot3+2

Answer 1

To simplify the expression 6/(√3 + 2), we need to rationalize the denominator by multiplying both the numerator and denominator by the conjugate of the denominator.

(6/(√3 + 2)) * ((√3 - 2)/(√3 - 2))
= (6√3 - 12)/((√3)^2 - 2^2)
= (6√3 - 12)/(3 - 4)
= (6√3 - 12)/(-1)
= -6√3 + 12

Therefore, 6/(√3 + 2) simplifies to -6√3 + 12.

Answer 2

wrong

Answer 3

Apologies for the mistake. Let's try again.

To simplify 6/(√3 + 2), we can rationalize the denominator by multiplying both the numerator and denominator by the conjugate of the denominator, which is (√3 - 2):

6/(√3 + 2) * (√3 - 2)/(√3 - 2)
= (6(√3 - 2))/(√3^2 - 2^2)
= (6√3 - 12)/(3 - 4)
= (6√3 - 12)/(-1)
= -6√3 + 12

Therefore, 6/(√3 + 2) simplifies to -6√3 + 12.

Answer 4

Wrong!!!

Answer 5

I apologize for the error in the previous responses. Let's correct it:

To simplify 6/(√3 + 2), we multiply both the numerator and denominator by the conjugate of the denominator, which is √3 - 2:

(6/(√3 + 2)) * ((√3 - 2)/(√3 - 2))

Expanding this gives us:

= (6√3 - 12)/(3 - 4)
= (6√3 - 12)/(-1)
= -6√3 + 12

Therefore, the correct simplification of 6/(√3 + 2) is -6√3 + 12. Thank you for your patience.

Answer 6

Simplify
6
--------------
√3+12

Answer 7

To simplify 6/(√3 + 12), we can simplify the denominator further by factoring out the common factor of 3:

6/(√3 + 12)
= 6/(√3 + 3*4)
= 6/(√3 + 2√3)
= 6/(3√3)
= 2/√3

Therefore, the simplified form of 6/(√3 + 12) is 2/√3.