1)show that squareroot3-squareroot2=1/squareroot3+squareroot2

Question

2)hence express ig(squareroot3-squareroot2) in terms of ig(squareroot3+squareroot2)

Answer 1

since (a+b)(a-b) = a^2-b^2

√3-√2 * (√3+√2)/(√3+√2)
= (3-2)/(√3+√2)

I assume by ig you mean log

log(√3-√2) = -log(√3+√2)