Asked by romaro
1)show that squareroot3-squareroot2=1/squareroot3+squareroot2
2)hence express ig(squareroot3-squareroot2) in terms of ig(squareroot3+squareroot2)
2)hence express ig(squareroot3-squareroot2) in terms of ig(squareroot3+squareroot2)
Answers
Answered by
Steve
since (a+b)(a-b) = a^2-b^2
√3-√2 * (√3+√2)/(√3+√2)
= (3-2)/(√3+√2)
I assume by ig you mean log
log(√3-√2) = -log(√3+√2)
√3-√2 * (√3+√2)/(√3+√2)
= (3-2)/(√3+√2)
I assume by ig you mean log
log(√3-√2) = -log(√3+√2)
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