Asked by Katherine

The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and y-intercept(b)?
Answered by GK
1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (y-b)/m
Let,
y = 1/lambda
m = -R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R)
Solve for nf

Answered by Katherine
These are the choices I can choose from:

A. (mb)^1/2
B. –mb^2
C. mb
D. (mb)^1/2
E. (–mb)^1/2
F. None of these are correct.

And when I solve for what you give me, I don't seem to have any of the answers but F. And I wanted to know if that was correct.
Answered by GK

nf would be the square root of some positive value, but your (A) and (B) look the same. Did you copy these alternate answers correctly?
Answered by Katherine
Yeah I copied the answers right.
I don't see how answer A and B are the same.
Answered by bob123
(–m/b)^1/2 - so is this the answer?
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