Asked by kiran
you mix 60.0 mL of 1.0 M silver nitrate with 25.0 mL of .80 M sodium chloride. what mass of silver chloride should you form?
Answers
Answered by
DrBob222
1.0 M x 0.060 L = moles AgNO3.
0.80 M x 0.0250 L = moles NaCl.
AgNO3 + NaCl ==> NaNO3 + AgCl.
This should help.
0.80 M x 0.0250 L = moles NaCl.
AgNO3 + NaCl ==> NaNO3 + AgCl.
This should help.
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