Asked by Jermain D

The Δ𝐻fus of silver is 11.30 kJ⋅mol−1 , and its Δ𝑆fus is 9.150 J⋅mol−1⋅K−1 . What is the melting point of silver?

T= ____ c?

Answers

Answered by DrBob222
dG = dH - TdS
0 = 11300 J - T(9.150)
Solve for T in kelvin
How did I know dG was zero? At the melting point of anything, the system is at equilibrium. Any system at equilibrium has dG = 0.
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