Asked by jose
evaluate
17-5to the 2nd powerdivde by(2 the fourth power + 3 to the 2nd power
17-5to the 2nd powerdivde by(2 the fourth power + 3 to the 2nd power
Answers
Answered by
Zoey
it's simple order of operations. the answer is 18
Answered by
PsyDAG
For future questions, this notation might be helpful.
"5to the 2nd power" is typed as 5^2 and read as "5 squared." However, with your question, it is hard to tell if you mean (17-5)^2 or just 5^2.
This is a rephrasing of your question:
(17 -5^2)/(2^4 + 3^2) = (17 + 25)/(16 + 9) = 42/25 = 1.68 (Remember that a negative times a negative becomes a positive.)
With the other interpretation, it
is:
(17-5)^2/(2^4 + 3^2) = (12^2)/25 = 144/25 = 5.76
I don't know how <B>Zoey</B> got 18.
I hope this helps. Thanks for asking.
"5to the 2nd power" is typed as 5^2 and read as "5 squared." However, with your question, it is hard to tell if you mean (17-5)^2 or just 5^2.
This is a rephrasing of your question:
(17 -5^2)/(2^4 + 3^2) = (17 + 25)/(16 + 9) = 42/25 = 1.68 (Remember that a negative times a negative becomes a positive.)
With the other interpretation, it
is:
(17-5)^2/(2^4 + 3^2) = (12^2)/25 = 144/25 = 5.76
I don't know how <B>Zoey</B> got 18.
I hope this helps. Thanks for asking.
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