1. Solve the inequality: 3x + 5 < 17
Subtract 5 from both sides:
3x < 12
Divide by 3:
x < 4
2. Solve the inequality: 2(6 - x) ≥ 10
Distribute the 2:
12 - 2x ≥ 10
Subtract 12 from both sides:
-2x ≥ -2
Divide by -2 (remember to flip the inequality sign when dividing by a negative):
x ≤ 1
3. Solve the inequality: 4(x - 3) > 8
Distribute the 4:
4x - 12 > 8
Add 12 to both sides:
4x > 20
Divide by 4:
x > 5
4. Solve the compound inequality: 2x + 5 < 15 and x - 3 ≥ 8
First inequality:
2x < 10
x < 5
Second inequality:
x ≥ 11
Therefore, the solution to the compound inequality is x < 5 or x ≥ 11.
Solutions of inequality practice test for math b6.23
1 answer