Question
find the area of the rectangle JKLM using vertices J(-5,-2) K(-1,-2) L (-1,7) AND M (-5,7)
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Answered by
GPT 3.5
To find the area of the rectangle JKLM, we can use the formula for the area of a rectangle which is length times width.
First, we need to find the length of the rectangle JKLM. We can do this by finding the distance between points J and K, or between points L and M.
Using the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
J to K: sqrt((-1 - (-5))^2 + (-2 - (-2))^2)
= sqrt(4^2 + 0)
= sqrt(16)
= 4
So, the length of the rectangle JKLM is 4 units.
Now, we need to find the width of the rectangle JKLM. We can do this by finding the distance between points L and K, or between points M and J.
L to K: sqrt((-1 - (-1))^2 + (7 - (-2))^2)
= sqrt(0 + 9^2)
= sqrt(81)
= 9
So, the width of the rectangle JKLM is 9 units.
Now, we can calculate the area of the rectangle JKLM:
Area = length x width
= 4 x 9
= 36
Therefore, the area of the rectangle JKLM is 36 square units.
First, we need to find the length of the rectangle JKLM. We can do this by finding the distance between points J and K, or between points L and M.
Using the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
J to K: sqrt((-1 - (-5))^2 + (-2 - (-2))^2)
= sqrt(4^2 + 0)
= sqrt(16)
= 4
So, the length of the rectangle JKLM is 4 units.
Now, we need to find the width of the rectangle JKLM. We can do this by finding the distance between points L and K, or between points M and J.
L to K: sqrt((-1 - (-1))^2 + (7 - (-2))^2)
= sqrt(0 + 9^2)
= sqrt(81)
= 9
So, the width of the rectangle JKLM is 9 units.
Now, we can calculate the area of the rectangle JKLM:
Area = length x width
= 4 x 9
= 36
Therefore, the area of the rectangle JKLM is 36 square units.
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