find the area of a rectangle with a length of (x^2+2x-3) and a width of (x+6)
2 answers
that would be (x^2+2x-3)(x+6) = _______
(x^2+2x-3)(x+6)
which is
= x (x^2+2x-3)
+ 6 (x^2+2x-3)
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which is
= x (x^2+2x-3)
+ 6 (x^2+2x-3)
------------------------