Asked by Jack

find the area of a rectangle with a length of (x^2+2x-3) and a width of (x+6)
Answered by oobleck
that would be (x^2+2x-3)(x+6) = _______
Answered by Anonymous
(x^2+2x-3)(x+6)
which is
= x (x^2+2x-3)
+ 6 (x^2+2x-3)
------------------------
There are no AI answers yet. The ability to request AI answers is coming soon!