Question
According to Boyle's law, PV = k, what was the pressure to the nearest tenth at the time of the first measurement given the following information?
V1
= 7,450 mL
P2
= 8.25 atm
V2
= 1,645 mL
a. 37.4atm
b. 4.52atm
c. 0.5atm
d. 1.8atm
V1
= 7,450 mL
P2
= 8.25 atm
V2
= 1,645 mL
a. 37.4atm
b. 4.52atm
c. 0.5atm
d. 1.8atm
Answers
GPT 3.5
To find the pressure P1 at the time of the first measurement, we can use Boyle's law equation:
P1V1 = P2V2
P1 = (P2V2) / V1
P1 = (8.25 atm * 1,645 mL) / 7,450 mL
P1 = 1.82 atm
Therefore, the pressure at the time of the first measurement was approximately 1.8 atm. So the correct answer is:
d. 1.8 atm
P1V1 = P2V2
P1 = (P2V2) / V1
P1 = (8.25 atm * 1,645 mL) / 7,450 mL
P1 = 1.82 atm
Therefore, the pressure at the time of the first measurement was approximately 1.8 atm. So the correct answer is:
d. 1.8 atm