240 = v/2L
240*(2*.640) = 307 ...
1st harmonic wavelength = 1.28
so, First Question: v = 307m/s &
wavelength = 1.28
frequency of 3rd harmonic = 3*f = 720
n = # of harmonic so 3*f = 3rd harmonic
720=n(v/(2L)) so n/(2L) = wavelength
3/(2*.640) = 2.34 m
Second Question: 2.34m
3(307/(2*.640))
This question has two parts:
First:
A typical steel B-string in a guitar resonates at its fundamental frequency at 240 Hertz. The length of the string is 0.640 m. What is the wave velocity along the string?.
Second:
Find the wavelength of the third harmonic of the guitar string
2 answers
A traveling wave in a string is given by y =0.03sin (2.2x - 3.5t) where y and X are in meters and t in seconds.find the amplitude, the wavelength, the frequency, the period and the speed of the wave
1 answer