Question

This question has two parts:

First:

A typical steel B-string in a guitar resonates at its fundamental frequency at 240 Hertz. The length of the string is 0.640 m. What is the wave velocity along the string?.

Second:

Find the wavelength of the third harmonic of the guitar string

Answer 1

240 = v/2L
240*(2*.640) = 307 ...
1st harmonic wavelength = 1.28
so, First Question: v = 307m/s &
wavelength = 1.28

frequency of 3rd harmonic = 3*f = 720

n = # of harmonic so 3*f = 3rd harmonic

720=n(v/(2L)) so n/(2L) = wavelength
3/(2*.640) = 2.34 m
Second Question: 2.34m

3(307/(2*.640))

Answer 2

A traveling wave in a string is given by y =0.03sin (2.2x - 3.5t) where y and X are in meters and t in seconds.find the amplitude, the wavelength, the frequency, the period and the speed of the wave