Asked by 123university
solve for x, to the nearest degree, in the interval 0degres less than andequal to x greater than and equal to 360degrees.
cos^2x=1
4cos^2x=1
cos^2x=1
4cos^2x=1
Answers
Answered by
Reiny
I will do the second one
4cos^2x=1
cos^2x = 1/4
cos x = ± 1/2
so x is in all 4 quadrants
we know cos 60º is 1/2
so x = 60º, 120º, 240º, 300º
the first one is even easier.
4cos^2x=1
cos^2x = 1/4
cos x = ± 1/2
so x is in all 4 quadrants
we know cos 60º is 1/2
so x = 60º, 120º, 240º, 300º
the first one is even easier.
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