Asked by Bob
Solve to the nearest thousandth.
5^1+x = 2^1-x
5^1+x = 2^1-x
Answers
Answered by
Henry
(1+x)*Log5 = (1-x)*Log2.
Divide both sides by Log5:
1+x = (1-x) * 0.431.
1+x = 0.431-0.431x.
1.431x = -0.569.
X = -0.398.
Divide both sides by Log5:
1+x = (1-x) * 0.431.
1+x = 0.431-0.431x.
1.431x = -0.569.
X = -0.398.
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