Systems of Linear Equations Unit Test

To solve this system of equations, we can use the method of substitution or elimination.

First, let's simplify the equations:

1) 6x - 3y = -6
2) 9x - 3y = -18

Let's set equation 1 and equation 2 equal to each other:

6x - 3y = 9x - 3y
-6 = 9x - 6x
-6 = 3x
x = -2

Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use equation 1:

6(-2) - 3y = -6
-12 - 3y = -6
-3y = -6 + 12
-3y = 6
y = -2

Therefore, the solution to the system of equations is (-2, -2).