Systems of Linear Equations Unit Test

To solve this system of equations, we can use the method of substitution. We can solve one of the equations for one variable and then substitute that expression into the other equation to solve for the other variable.

From the second equation, we can solve for y:
-6x + y = 32
y = 6x + 32

Now, we can substitute this into the first equation:
4x - 8(6x + 32) = -36
4x - 48x - 256 = -36
-44x - 256 = -36
-44x = 220
x = -5

Now that we have found the value of x, we can substitute it back into the second equation to find y:
-6(-5) + y = 32
30 + y = 32
y = 2

Therefore, the solution to the system of equations is (-5, 2).