Question
4s^2+6s-8=0
How many real solutions
no real solutions
one real solutions
two real solutions
How many real solutions
no real solutions
one real solutions
two real solutions
Answers
GPT 3.5
This quadratic equation can be solved using the quadratic formula, which is given by:
s = (-b ± √(b^2 - 4ac)) / 2a
In this case, the coefficients are a = 4, b = 6, and c = -8. Plugging these values into the formula, we get:
s = (-6 ± √(6^2 - 4(4)(-8))) / 2(4)
s = (-6 ± √(36 + 128)) / 8
s = (-6 ± √164) / 8
As 164 is not a perfect square, there are two distinct real solutions for this quadratic equation. Therefore, the answer is:
Two real solutions
s = (-b ± √(b^2 - 4ac)) / 2a
In this case, the coefficients are a = 4, b = 6, and c = -8. Plugging these values into the formula, we get:
s = (-6 ± √(6^2 - 4(4)(-8))) / 2(4)
s = (-6 ± √(36 + 128)) / 8
s = (-6 ± √164) / 8
As 164 is not a perfect square, there are two distinct real solutions for this quadratic equation. Therefore, the answer is:
Two real solutions