Asked by ariana
-7x^2+6x+3=0
how many real number solutions does the equation have
can you explain it by doing it...i don't get it...baby steps please
thank you
how many real number solutions does the equation have
can you explain it by doing it...i don't get it...baby steps please
thank you
Answers
Answered by
R_scott
the discriminant (b^2 - 4 a c) shows the nature of the roots (solutions)
6^2 - (4 * -7 * 3) = 36 - -84 = 120
a positive discriminant means two real roots
6^2 - (4 * -7 * 3) = 36 - -84 = 120
a positive discriminant means two real roots
Answered by
henry2,
-7x^2+6x+3 = 0.
h = Xv = -B/2A = -6/-14 = 3/7 = .
k = Yv = -7(3/7)^2 + 6(3/7) + 3 = -9/7 + 18/7 + 21/7 = 30/7 = 4.3.
V(h, k) = V(0.43, 4.3).
For a parabola that opens downward:
k < o. No real solution.
k = 0. 1 real solution.
k > 0. 2 real solutions.
h = Xv = -B/2A = -6/-14 = 3/7 = .
k = Yv = -7(3/7)^2 + 6(3/7) + 3 = -9/7 + 18/7 + 21/7 = 30/7 = 4.3.
V(h, k) = V(0.43, 4.3).
For a parabola that opens downward:
k < o. No real solution.
k = 0. 1 real solution.
k > 0. 2 real solutions.