Question

Find the area of rectangle ABCD , with vertices A(1,7) , B(3,7) , C(3,−4) , and D(1,−4) .
(1 point) units by the power of 2

Answer 1

Find the area of rectangle QRST, with vertices Q(−1,7), R(5,7), S(5,3), and T(−1,3).(1 point) units by the power of 2

Answer 2

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Answer 3

To find the area of the rectangle, we need to find the length of the base and the height.

The base of the rectangle is the distance between points A and B. Using the distance formula:
AB = √((3-1)^2 + (7-7)^2)
AB = √(2^2 + 0^2)
AB = √4
AB = 2

The height of the rectangle is the distance between points B and C. Using the distance formula:
BC = √((3-3)^2 + (7-(-4))^2)
BC = √(0^2 + 11^2)
BC = √121
BC = 11

Therefore, the area of the rectangle ABCD is:
Area = base x height
Area = 2 x 11
Area = 22 square units.

Answer 4

To find the area of the rectangle QRST, we need to find the length of the base and the height.

The base of the rectangle is the distance between points Q and R. Using the distance formula:
QR = √((5-(-1))^2 + (7-7)^2)
QR = √(6^2 + 0^2)
QR = √36
QR = 6

The height of the rectangle is the distance between points R and S. Using the distance formula:
RS = √((5-5)^2 + (7-3)^2)
RS = √(0^2 + 4^2)
RS = √16
RS = 4

Therefore, the area of the rectangle QRST is:
Area = base x height
Area = 6 x 4
Area = 24 square units.

Answer 5

I apologize for the mistake. Let's correct it:

To find the area of the rectangle QRST, we need to find the length of the base and the height.

The base of the rectangle is the distance between points Q and R. Using the distance formula:
QR = √((5 - (-1))^2 + (7 - 7)^2)
QR = √(6^2 + 0^2)
QR = √36
QR = 6

The height of the rectangle is the distance between points S and R. Using the distance formula:
SR = √((5 - 5)^2 + (3 - 7)^2)
SR = √(0^2 + (-4)^2)
SR = √16
SR = 4

Therefore, the area of the rectangle QRST is:
Area = base x height
Area = 6 x 4
Area = 24 square units.