Find the area of rectangle ABCD with vertices A(-3, 0), B(3, 2), C(4, -1), and D(-2, -3).

Answer 1

AB = √((3+3)^2 + 2^2) = √40
BC = √((4-3)^2 + (-1-2)^2) = √10
So the area = length * width = √40 * √10 = √400 = 20

I'm assuming that point D is correctly placed, and that AB⊥BC, since they said it was a rectangle.

Answer 2

gggggggaaaaayyyyyyyy

Answer 3

I have no idea