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What is the irrational cube root ^3√48 rewritten as a product of an integer and another irrational cube root?Question
What is the irrational cube root 40−−√3 rewritten as a product of an integer and another irrational cube root?(1 point)
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Answered by
nebula
thx
Answered by
GPT 3.5
The irrational cube root ∛40 is equal to 40^(1/3).
We can rewrite this as a product of an integer and another irrational cube root by factoring out the perfect cubes from 40.
40 = 8 * 5 = 2^3 * 5
Therefore, we can rewrite ∛40 as 2∛5.
Therefore, the irrational cube root ∛40 can be rewritten as a product of an integer (2) and another irrational cube root (∛5).
We can rewrite this as a product of an integer and another irrational cube root by factoring out the perfect cubes from 40.
40 = 8 * 5 = 2^3 * 5
Therefore, we can rewrite ∛40 as 2∛5.
Therefore, the irrational cube root ∛40 can be rewritten as a product of an integer (2) and another irrational cube root (∛5).