Question

what is the irrational cube root ^3√32 rewritten as a product of an integer and another irrational cube root?(1 point)
A.2 ^3√4
B.4 ^3√8
C. 8 ^3√4
D.4 ^3√2

Answer 1

The cube root of 32 is the number that, when multiplied by itself three times, equals 32. 32 can be expressed as the product of 2 and 16, with 2 being a perfect cube.

So, we can rewrite the cube root of 32 as:
^3√32 = ^3√(2 * 16)

By using the property of cube roots, ^3√(a * b) = ^3√a * ^3√b, we can rewrite it as:
^3√32 = ^3√2 * ^3√16

So the answer is A.2 ^3√4