Asked by Priscilla

What is the kinetic energy of an electron {mass = 9.1 x 10^ - 31 kg} when it is moving at 3.0 x 10^7 m/s {1/10 the velocity of light}?

KE = 1/2 m v^2
KE = 1/2 (9.1 x 10^ - 31)(3.0 x 10^7)
KE = 1.365 x 10^ -23

I don't know if this is right because what got me confused is the 1/10 the velocity of light.
Answered by bobpursley
No. You did not square velocity.
There are no AI answers yet. The ability to request AI answers is coming soon!