Asked by Anonymous
Identify the point of intersection of these two curves:
P(t)=300(1.05)^t
F(t)=1000(0.92)^t
P(t)=300(1.05)^t
F(t)=1000(0.92)^t
Answers
Answered by
bobpursley
300(1.05)^t=1000(.92^t)
take the log of each side..
log 300+tlog1.05=log1000+tlog.92
t(log1.05-log.92)=log 1000-log300
t(log(1.05/.92)=log(1000/300)
t= log(920/315)=.465
check my math.
take the log of each side..
log 300+tlog1.05=log1000+tlog.92
t(log1.05-log.92)=log 1000-log300
t(log(1.05/.92)=log(1000/300)
t= log(920/315)=.465
check my math.
Answered by
Jonathan
you did it right up until:
t = log(920/314) = 0.465, I have no idea how you got those numbers but it's
t(log(1.05/.92))=log(1000/300)
t(log(1.1141304348)=log(3.3(rpt.))
t(0.057401472)=0.522878745
t=(0.522878745)/(0.057401472)
t=9.1092
t = log(920/314) = 0.465, I have no idea how you got those numbers but it's
t(log(1.05/.92))=log(1000/300)
t(log(1.1141304348)=log(3.3(rpt.))
t(0.057401472)=0.522878745
t=(0.522878745)/(0.057401472)
t=9.1092
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