300(1.05)^t=1000(.92^t)
take the log of each side..
log 300+tlog1.05=log1000+tlog.92
t(log1.05-log.92)=log 1000-log300
t(log(1.05/.92)=log(1000/300)
t= log(920/315)=.465
check my math.
Identify the point of intersection of these two curves:
P(t)=300(1.05)^t
F(t)=1000(0.92)^t
2 answers
you did it right up until:
t = log(920/314) = 0.465, I have no idea how you got those numbers but it's
t(log(1.05/.92))=log(1000/300)
t(log(1.1141304348)=log(3.3(rpt.))
t(0.057401472)=0.522878745
t=(0.522878745)/(0.057401472)
t=9.1092
t = log(920/314) = 0.465, I have no idea how you got those numbers but it's
t(log(1.05/.92))=log(1000/300)
t(log(1.1141304348)=log(3.3(rpt.))
t(0.057401472)=0.522878745
t=(0.522878745)/(0.057401472)
t=9.1092
1 answer