Asked by Aly
A boy throws a 4-kg pumpkin at 8m/s to a 40kg girl on roller skates, who catches it. At what speed does the girl then move backwards?
Answers
Answered by
MathMate
Assume the girl was facing the boy, and was stationary before catching the pumpkin.
Her initial momentum is zero.
Momentum of the punmkin
= 4 kg * 8 m/s
= 32 kg-m/s
Combined mass of girl and pumpkin
= 4+40
= 44 kg
Final velocity
= 32 kg-m-s<sup>-1</sup> / 44 kg
= 8/11 m/s
Her initial momentum is zero.
Momentum of the punmkin
= 4 kg * 8 m/s
= 32 kg-m/s
Combined mass of girl and pumpkin
= 4+40
= 44 kg
Final velocity
= 32 kg-m-s<sup>-1</sup> / 44 kg
= 8/11 m/s
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