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A 7.77 kg pumpkin falls from a height of 12.3m. It hits the ground and comes to an abrupt stop in about 444 ms. What is the average force imparted by the ground (aka 'Normal Force') on the pumpkin?
8 years ago

Answers

Scott
1/2 m v^2 = m g h

v = √(2 g h)

f = m a

mass is 7.77 kg

acceleration is ... √(2 g h) / .444 s
8 years ago
Anonymous
iahd
7 years ago

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