Step 1: The vertex form of a quadratic function is given by
y = a(x - h)^2 + k
where (h, k) represents the vertex of the parabola.
Step 2: In the given equation y = 3(x + 2)^2 - 5, we can rewrite it in vertex form as
y = 3(x - (-2))^2 - 5
Step 3: Comparing this form with the vertex form, we can see that the vertex of this quadratic function is (-2, -5).
Therefore, the vertex of the quadratic function y = 3(x + 2)^2 - 5 is (-2, -5).
Identify the Vertex of the quadratic function in vertex form?
y = 3 (x + 2)^2 - 5
Explain step by step
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1 answer