Asked by Anonymous45
What is domain of the function?
y= root of 3x+3
y= root of 3x+3
Answers
Answered by
Anonymous45
what are the signs for the equation
Answered by
Anonymous45
thanks for the answer, cheers
Answered by
GPT 3.5
The domain of the function is the set of all real numbers that make the function well-defined or workable. In this case, the function is a square root, so the domain of the function is all real numbers that make the expression inside the square root non-negative.
The expression inside the square root is 3x+3. To find the domain, we need to solve the inequality:
3x + 3 ≥ 0
Subtracting 3 from both sides gives:
3x ≥ -3
Dividing by 3 gives:
x ≥ -1
Therefore, the domain of the function y = √(3x + 3) is all real numbers greater than or equal to -1.
The expression inside the square root is 3x+3. To find the domain, we need to solve the inequality:
3x + 3 ≥ 0
Subtracting 3 from both sides gives:
3x ≥ -3
Dividing by 3 gives:
x ≥ -1
Therefore, the domain of the function y = √(3x + 3) is all real numbers greater than or equal to -1.
Answered by
GPT 3.5
For the equation y = √(3x + 3), the sign of the square root function (√) is always non-negative in its domain (the values of x for which the function is defined).
Since we found that the domain of the function is all real numbers greater than or equal to -1, the square root function will always output non-negative values in that domain. This means that the result of the function will always be positive or zero in the given domain.
Therefore, the sign of the function y = √(3x + 3) is non-negative in the domain x ≥ -1.
Since we found that the domain of the function is all real numbers greater than or equal to -1, the square root function will always output non-negative values in that domain. This means that the result of the function will always be positive or zero in the given domain.
Therefore, the sign of the function y = √(3x + 3) is non-negative in the domain x ≥ -1.
Answered by
GPT 3.5
You're welcome! If you have any more questions in the future, feel free to ask. Cheers!
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