Question

Solve Systems Of Linear Equations. Ex: (x,y) for answer
1. 2x - 4y = -2
-8x + 4y = 8
2. -2x + 2y = -14
2x + 6y = -10
3. 9x - 4y = -20
-3x + 4y = 20
4. -5x + 7y = 12
-5x + 6y = 11
5. -3x - 9y = 6
x - 9y = 10
6. -7x + 6y = -1
-7x - 3y = -10

Answer 1

1 and 2 are wrong

Answer 2

both r wrong

Answer 3

4. -5x + 7y = 12
-5x + 6y = 11
5. -3x - 9y = 6
x - 9y = 10
6. -7x + 6y = -1
-7x - 3y = -10

Answer 4

1. (1, 1)
2. (-2, -6)
3. (0, 5)
4. No solution (parallel lines)
5. (1, -16/3)
6. (1, 3)

Answer 5

1. (2, 1)
2. (-2, -6)

Answer 6

I apologize for the mistake. Let's try solving them again:

1.
2x - 4y = -2
-8x + 4y = 8

Adding the two equations together:
-6x = 6
x = -1

Substitute x = -1 into the first equation:
2(-1) - 4y = -2
-2 - 4y = -2
-4y = 0
y = 0

Therefore, the solution is (-1, 0).

2.
-2x + 2y = -14
2x + 6y = -10

Adding the two equations together:
8y = -24
y = -3

Substitute y = -3 into the first equation:
-2x + 2(-3) = -14
-2x - 6 = -14
-2x = -8
x = 4

Therefore, the solution is (4, -3).

Answer 7

4.
-5x + 7y = 12
-5x + 6y = 11

Subtracting the second equation from the first:
y = 1

Substitute y = 1 into either equation:
-5x + 7 = 12
-5x = 5
x = -1

Therefore, the solution is (-1, 1).

5.
-3x - 9y = 6
x - 9y = 10

Subtracting the second equation from the first:
-4x = -4
x = 1

Substitute x = 1 into either equation:
-3(1) - 9y = 6
-3 - 9y = 6
-9y = 9
y = -1

Therefore, the solution is (1, -1).

6.
-7x + 6y = -1
-7x - 3y = -10

Subtracting the second equation from the first:
9y = 9
y = 1

Substitute y = 1 into either equation:
-7x + 6 = -1
-7x = -7
x = 1

Therefore, the solution is (1, 1).