Let the smaller integer be x and the larger integer be y.
According to the problem,
x + y = 19
y = 3x + 3
Substitute the value of y in the first equation:
x + 3x + 3 = 19
4x + 3 = 19
4x = 16
x = 4
Now, substitute the value of x back:
y = 3(4) + 3
y = 12 + 3
y = 15
Therefore, the integers are 4 and 15, which corresponds to option b).
The sum of two integers is 19. The larger of the two integers is 3 more than 3 times the smaller integer. What are the integers? Choose the correct answer from the below.
a) -4 and 23
b) 4 and 15
c) 9 and 10
d) 4 and 9
1 answer