What two integers does v76 lie between?

Question

v76 is greater than the square root of the perfect square Question Blank 1 of 4
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v76 is less than the square root of the perfect square Question Blank 2 of 4
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v76 Of the two is closer to the square root of Question Blank 3 of 4
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so an estimate for v76 is approximately Question Blank 4 of 4
Answer

Answer 1

To find the value of $v76$ (which might refer to the 76th term in a sequence or some specific numerical context), let's assume you are asking for the square root of 76, or possibly an estimate based on perfect squares.

1. Finding the Perfect Squares:

   • The perfect squares around 76 are $64$ (which is $8^2$) and $81$ (which is $9^2$).
   • Therefore, we can conclude: $$8<\sqrt{76}<9$$

2. Answering the Questions:

   • Question Blank 1 of 4: v76 is greater than the square root of the perfect square $64$.
   • Question Blank 2 of 4: v76 is less than the square root of the perfect square $81$.
   • Question Blank 3 of 4: The value $76$ is closer to $81$ than to $64$ (since 76 is significantly closer to 81).
   • Question Blank 4 of 4: An estimate for $v76$ is approximately $8.7$ (since $\sqrt{76}\approx 8.717$).

Summary of Answers:

1. 8
2. 9
3. 9
4. Approximately 8.7