Question

What two integers does v76 lie between?



v76 is greater than the square root of the perfect square Question Blank 1 of 4
Answer



v76 is less than the square root of the perfect square Question Blank 2 of 4
Answer



v76 Of the two is closer to the square root of Question Blank 3 of 4
Answer
so an estimate for v76 is approximately Question Blank 4 of 4
Answer

Answer 1

To find the value of \( v76 \) (which might refer to the 76th term in a sequence or some specific numerical context), let's assume you are asking for the square root of 76, or possibly an estimate based on perfect squares.

1. **Finding the Perfect Squares**:
- The perfect squares around 76 are \( 64 \) (which is \( 8^2 \)) and \( 81 \) (which is \( 9^2 \)).
- Therefore, we can conclude:
\[
8 < \sqrt{76} < 9
\]

2. **Answering the Questions**:
- **Question Blank 1 of 4**: v76 is greater than the square root of the perfect square \( 64 \).
- **Question Blank 2 of 4**: v76 is less than the square root of the perfect square \( 81 \).
- **Question Blank 3 of 4**: The value \( 76 \) is closer to \( 81 \) than to \( 64 \) (since 76 is significantly closer to 81).
- **Question Blank 4 of 4**: An estimate for \( v76 \) is approximately \( 8.7 \) (since \( \sqrt{76} \approx 8.717 \)).

Summary of Answers:
1. 8
2. 9
3. 9
4. Approximately 8.7