Question

Solve the system of equations.
–x+6y=13
4x–10y=–10 (1 point)
(___, ___)

Answer 1

wrong

Answer 2

...

Answer 3

thats not right bot

Answer 4

(3, 2)

Answer 5

To solve the system of equations -x + 6y = 13 and 4x - 10y = -10, we can use the method of substitution or elimination.

1. Solve the first equation for x:
-x + 6y = 13
x = 6y + 13

2. Substitute the expression for x into the second equation:
4(6y + 13) - 10y = -10
24y + 52 - 10y = -10
14y + 52 = -10
14y = -62
y = -62/14
y = -31/7

3. Substitute the value of y back into the first equation to find x:
x = 6(-31/7) + 13
x = -186/7 + 13
x = (-186 + 91)/7
x = -95/7

Therefore, the solution to the system of equations is (-95/7, -31/7).

Answer 6

Let's eliminate the variable x in the system of equations:

1. -x + 6y = 13
2. 4x - 10y = -10

From the first equation, we get x = 6y + 13.

Substitute this expression for x into the second equation:

4(6y + 13) - 10y = -10
24y + 52 - 10y = -10
14y + 52 = -10
14y = -62
y = -62/14
y = -31/7

Now we can substitute y back into the expression x = 6y + 13:

x = 6(-31/7) + 13
x = -186/7 + 13
x = -186/7 + 91/7
x = -95/7

Therefore, the solution to the system of equations is (-95/7, -31/7).

Answer 7

Let's solve the system of equations -x + 6y = 13 and 4x - 10y = -10 using the elimination method:

1. Multiply the first equation by 4 to match the coefficients of x:
-4x + 24y = 52

2. Add this modified first equation to the second equation:
-4x + 24y + 4x - 10y = 52 - 10
14y = 42
y = 3

3. Substitute y = 3 back into the first equation:
-x + 6(3) = 13
-x + 18 = 13
-x = -5
x = 5

Therefore, the solution to the system of equations is (5, 3).