x^2-y^2-6x+8y-3=0
x^2 - 6x + 9 - (y^2 - 8y + 16) = 3 + 9 + -16
(x-3)^2 - (y-4)^2 = -4
(x-3)^2/4 - (y-4)^2/4 = -1
You should be able to take it from there
x^2-y^2-6x+8y-3=0
Find the center vertices, foci, and asymptotes for the hyperbola.
1 answer