Asked by Nick
x^2-y^2-6x+8y-3=0
Find the center vertices, foci, and asymptotes for the hyperbola.
Find the center vertices, foci, and asymptotes for the hyperbola.
Answers
Answered by
Reiny
x^2-y^2-6x+8y-3=0
x^2 - 6x + <b>9</b> - (y^2 - 8y + <b>16</b>) = 3 + <b>9</b> + <b>-16</b>
(x-3)^2 - (y-4)^2 = -4
(x-3)^2/4 - (y-4)^2/4 = -1
You should be able to take it from there
x^2 - 6x + <b>9</b> - (y^2 - 8y + <b>16</b>) = 3 + <b>9</b> + <b>-16</b>
(x-3)^2 - (y-4)^2 = -4
(x-3)^2/4 - (y-4)^2/4 = -1
You should be able to take it from there
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